(0) Obligation:

Clauses:

map([], L) :- ','(!, eq(L, [])).
map(X, .(Y, Ys)) :- ','(head(X, H), ','(tail(X, T), ','(p(H, Y), map(T, Ys)))).
head([], X1).
head(.(H, X2), H).
tail([], []).
tail(.(X3, T), T).
p(X, Y).
eq(X, X).

Query: map(g,a)

(1) PrologToDTProblemTransformerProof (SOUND transformation)

Built DT problem from termination graph DT10.

(2) Obligation:

Triples:

mapA(.(X1, X2), .(X3, X4)) :- mapA(X2, X4).

Clauses:

mapcA([], []).
mapcA(.(X1, X2), .(X3, X4)) :- mapcA(X2, X4).

Afs:

mapA(x1, x2)  =  mapA(x1)

(3) TriplesToPiDPProof (SOUND transformation)

We use the technique of [DT09]. With regard to the inferred argument filtering the predicates were used in the following modes:
mapA_in: (b,f)
Transforming TRIPLES into the following Term Rewriting System:
Pi DP problem:
The TRS P consists of the following rules:

MAPA_IN_GA(.(X1, X2), .(X3, X4)) → U1_GA(X1, X2, X3, X4, mapA_in_ga(X2, X4))
MAPA_IN_GA(.(X1, X2), .(X3, X4)) → MAPA_IN_GA(X2, X4)

R is empty.
The argument filtering Pi contains the following mapping:
mapA_in_ga(x1, x2)  =  mapA_in_ga(x1)
.(x1, x2)  =  .(x2)
MAPA_IN_GA(x1, x2)  =  MAPA_IN_GA(x1)
U1_GA(x1, x2, x3, x4, x5)  =  U1_GA(x2, x5)

We have to consider all (P,R,Pi)-chains

Infinitary Constructor Rewriting Termination of PiDP implies Termination of TRIPLES

(4) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

MAPA_IN_GA(.(X1, X2), .(X3, X4)) → U1_GA(X1, X2, X3, X4, mapA_in_ga(X2, X4))
MAPA_IN_GA(.(X1, X2), .(X3, X4)) → MAPA_IN_GA(X2, X4)

R is empty.
The argument filtering Pi contains the following mapping:
mapA_in_ga(x1, x2)  =  mapA_in_ga(x1)
.(x1, x2)  =  .(x2)
MAPA_IN_GA(x1, x2)  =  MAPA_IN_GA(x1)
U1_GA(x1, x2, x3, x4, x5)  =  U1_GA(x2, x5)

We have to consider all (P,R,Pi)-chains

(5) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 1 less node.

(6) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

MAPA_IN_GA(.(X1, X2), .(X3, X4)) → MAPA_IN_GA(X2, X4)

R is empty.
The argument filtering Pi contains the following mapping:
.(x1, x2)  =  .(x2)
MAPA_IN_GA(x1, x2)  =  MAPA_IN_GA(x1)

We have to consider all (P,R,Pi)-chains

(7) PiDPToQDPProof (SOUND transformation)

Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

MAPA_IN_GA(.(X2)) → MAPA_IN_GA(X2)

R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.

(9) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • MAPA_IN_GA(.(X2)) → MAPA_IN_GA(X2)
    The graph contains the following edges 1 > 1

(10) YES